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X=(-16X^2)+30X+4
We move all terms to the left:
X-((-16X^2)+30X+4)=0
We calculate terms in parentheses: -((-16X^2)+30X+4), so:We get rid of parentheses
(-16X^2)+30X+4
We get rid of parentheses
-16X^2+30X+4
Back to the equation:
-(-16X^2+30X+4)
16X^2-30X+X-4=0
We add all the numbers together, and all the variables
16X^2-29X-4=0
a = 16; b = -29; c = -4;
Δ = b2-4ac
Δ = -292-4·16·(-4)
Δ = 1097
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1097}}{2*16}=\frac{29-\sqrt{1097}}{32} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1097}}{2*16}=\frac{29+\sqrt{1097}}{32} $
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